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*AGRIC PRACTICAL SOLUTION*
(1a.)
A:clay
B:Sand
(1b) The sandy soil sample B has a lower water retention capacity compared to the clay soil sample A. Sandy soil has larger particles and larger pore spaces, allowing water to drain through more quickly and reducing its water-holding capacity.
(1c) Calculation of the percentage of water retained:
(i) Cylinder A:
Percentage of water retained = (Water collected / Water added) x 100
= (10 cm³ / 30 cm³) x 100
= 33.33%
(ii) Cylinder B:
Percentage of water retained = (Water collected / Water added) x 100
= (25 cm³ / 30 cm³) x 100
= 83.33%
(iii) Two crops that could thrive in clay soil (sample A):
– Wheat
– Rice
Two crops that could thrive in sandy soil (sample B):
– Maize
– Sunflowers
(4)
(a) To determine the plant population for groundnut, we need to calculate the total number of plants that can be accommodated in the given area of farmland.
Area of farmland for groundnut = 3 hectares = 30000 m² (1 hectare = 10000 m²)
Spacing for groundnut = 1m x 0.5m = 0.5 m²
Plant population for groundnut = Area of farmland / Spacing
= 30000 m² / 0.5 m²
= 60000 plants
Therefore, the plant population for groundnut is 60000.
(b) To calculate the expected plant population of maize, we need to consider the germination percentage and the area of farmland.
Area of farmland for maize = 5 hectares = 50000 m²
Spacing for maize = 1m x 1m = 1 m²
Plant population for maize = Area of farmland / Spacing
= 50000 m² / 1 m²
= 50000 plants
Expected plant population of maize (taking into account the germination percentage) = Germination percentage / 100 x Plant population
= 90 / 100 x 50000
= 45000 plants
Therefore, the expected plant population of maize on the farmland is 45000.
(c)
(ii) Temperature
(iii) Oxygen availability
(d)
(i) Weeding
(ii) Fertilization
[11/17, 3:55 PM] Marita, Jr.: *AGRIC PRACTICAL SOLUTION*
(1a.)
A:clay
B:Sand
(1b) The sandy soil sample B has a lower water retention capacity compared to the clay soil sample A. Sandy soil has larger particles and larger pore spaces, allowing water to drain through more quickly and reducing its water-holding capacity.
(1c) Calculation of the percentage of water retained:
(i) Cylinder A:
Percentage of water retained = (Water collected / Water added) x 100
= (10 cm³ / 30 cm³) x 100
= 33.33%
(ii) Cylinder B:
Percentage of water retained = (Water collected / Water added) x 100
= (25 cm³ / 30 cm³) x 100
= 83.33%
(iii) Two crops that could thrive in clay soil (sample A):
– Wheat
– Rice
Two crops that could thrive in sandy soil (sample B):
– Maize
– Sunflowers
*WAEC GCE AGRIC PRACTICAL*
*NUMBER ONE*
(1a)
A: Clay soil
B: Sandy soil
(1b)
Sandy soil
(1c)
(i) Cylinder A:
Percentage of water retained in A
= (10/30) x 100
= 33.3%
(ii) Cylinder B:
Percentage of water retained in B
= (25/30) x 100
= 83.3%
(1d)
A:
(i) Wheat
(ii) Barley
B:
(i) Carrots
(ii) Potatoes
*WAEC GCE AGRIC*
*NUMBER THREE*
(a) To determine the plant population for groundnut, we need to calculate the total number of plants that can be accommodated in the given area of farmland.
Area of farmland for groundnut = 3 hectares = 30000 m² (1 hectare = 10000 m²)
Spacing for groundnut = 1m x 0.5m = 0.5 m²
Plant population for groundnut = Area of farmland / Spacing
= 30000 m² / 0.5 m²
= 60000 plants
Therefore, the plant population for groundnut is 60000.
(b) To calculate the expected plant population of maize, we need to consider the germination percentage and the area of farmland.
Area of farmland for maize = 5 hectares = 50000 m²
Spacing for maize = 1m x 1m = 1 m²
Plant population for maize = Area of farmland / Spacing
= 50000 m² / 1 m²
= 50000 plants
Expected plant population of maize (taking into account the germination percentage) = Germination percentage / 100 x Plant population
= 90 / 100 x 50000
= 45000 plants
Therefore, the expected plant population of maize on the farmland is 45000.
(c)
(i) Moisture
(ii) Temperature
(iii)Oxygen availability
(d)
(i) Weeding
(ii) Fertilization
Accurately correct 💯 thanks boss
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